C\u00e1ch b\u1eaft ch\u1ea1m \u0111\u1ec1 chu\u1ea9n nh\u1ea5t<\/figcaption><\/figure>\nDo \u0111\u00f3, \u0111\u1ec3 bi\u1ebft \u0111\u1ebfn c\u00e1c ph\u01b0\u01a1ng ph\u00e1p nu\u00f4i ch\u1ea1m \u0111\u1eb7c bi\u1ec7t, c\u00e1ch b\u1eaft ch\u1ea1m \u0111\u1ec1 nu\u00f4i trong tu\u1ea7n, trong ng\u00e0y. Anh em c\u00f3 th\u1ec3 tham kh\u1ea3o nh\u1eefng th\u00f4ng tin sau \u0111\u00e2y ch\u00fang t\u00f4i cung c\u1ea5p v\u1ec1 c\u00e1ch b\u1eaft ch\u1ea1m \u0111\u1ec1 chu\u1ea9n nh\u00e9.<\/span><\/p>\nT\u00ednh d\u00e0n ch\u1ea1m \u0111\u1ec1 1:<\/em><\/strong><\/span><\/span><\/h3>\n\u0110\u1ec3 nu\u00f4i \u0111\u1ec1 ch\u1ea1m 1, anh em c\u1ea7n ph\u1ea3i d\u1ef1a tr\u00ean k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc ng\u00e0y ch\u1ee7 nh\u1eadt h\u00e0ng tu\u1ea7n. X\u00e9t th\u1ea5y s\u1ed1 gi\u1eefa xu\u1ea5t hi\u1ec7n \u1edf gi\u1ea3i nh\u1ea5t ng\u00e0y ch\u1ee7 nh\u1eadt l\u00e0 1 th\u00ec s\u1eed d\u1ee5ng \u0111\u1ec3 nu\u00f4i \u0111\u00e1nh ch\u1ea1m \u0111\u1ebfn th\u1ee9 7 tu\u1ea7n sau. Theo c\u00e1c cao th\u1ee7 l\u00e3o l\u00e0ng th\u00ec c\u00e1ch b\u1eaft ch\u1ea1m \u0111\u1ec1 chu\u1ea9n n\u00e0y c\u1ef1c k\u1ef3 hi\u1ec7u qu\u1ea3, \u0111\u00e3 c\u00f3 kh\u00f4ng \u00edt ng\u01b0\u1eddi \u00e1p d\u1ee5ng v\u00e0 tr\u00fang l\u1edbn. Do \u0111\u00f3, h\u00e3y \u0111\u1ec3 \u00fd v\u00e0 th\u1eed v\u1eadn may c\u1ee7a m\u00ecnh nh\u00e9.\u00a0<\/span><\/p>\nV\u00ed d\u1ee5:<\/strong>\u00a0H\u00f4m nay l\u00e0 ch\u1ee7 nh\u1eadt v\u00e0 k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc c\u00f3 gi\u1ea3i nh\u1ea5t v\u1ec1 67199. Nh\u1eadn th\u1ea5y s\u1ef1 xu\u1ea5t hi\u1ec7n c\u1ee7a s\u1ed1 1 \u1edf ch\u00ednh gi\u1eefa th\u00ec \u0111\u00e1nh ch\u1ea1m \u0111\u1ec1 1 t\u1eeb th\u1ee9 2 \u0111\u1ebfn th\u1ee9 7. Kh\u1ea3 n\u0103ng cao ng\u00e0y th\u1ee9 3, th\u1ee9 4 l\u00e0 \u0111\u01b0\u1ee3c \u0103n.\u00a0<\/span><\/p>\nC\u00e1ch b\u1eaft ch\u1ea1m \u0111\u1ec3 chu\u1ea9n d\u1ef1a v\u00e0o t\u1ed5ng \u0111\u1ec1:<\/em><\/strong><\/span><\/span><\/h3>\nTheo kinh nghi\u1ec7m c\u1ee7a nh\u1eefng cao th\u1ee7 th\u00ec b\u1eaft \u0111\u1ec1 ch\u1ea1m 2 s\u1ebd cho ng\u01b0\u1eddi ch\u01a1i \u0103n kho\u1ea3ng 3 \u2013 4 tu\u1ea7n li\u00ean t\u1ee5c. Sau \u0111\u00f3, ng\u01b0\u1eddi ch\u01a1i ph\u1ea3i ngh\u1ec9 1-2 tu\u1ea7n r\u1ed3i m\u1edbi ti\u1ebfp t\u1ee5c ch\u01a1i l\u1ea1i.<\/span><\/p>\n\u0110\u1ec3 th\u1ef1c hi\u1ec7n c\u00e1ch b\u1eaft ch\u1ea1m \u0111\u1ec1 chu\u1ea9n n\u00e0y th\u00ec anh em c\u1ea7n ph\u1ea3i quan t\u00e2m \u0111\u1ebfn t\u1ed5ng \u0111\u1ec3 c\u1ee7a ng\u00e0y ch\u1ee7 nh\u1eadt. Sau \u0111\u00f3, l\u1ea5y t\u1ed5ng n\u00e0y gh\u00e9p v\u1edbi \u0111u\u00f4i c\u1ee7a \u0111\u1ec1 th\u1ee9 6 tu\u1ea7n tr\u01b0\u1edbc. Nh\u01b0 v\u1eady ch\u00fang ta s\u1ebd c\u00f3 \u0111\u01b0\u1ee3c b\u1ed9 s\u1ed1 \u0111\u1ec1 v\u00e0 nu\u00f4i 1 tu\u1ea7n.\u00a0<\/span><\/p>\nV\u00ed d\u1ee5:<\/strong>\u00a0Th\u1ed1ng k\u00ea x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc th\u1ee9 6 tu\u1ea7n tr\u01b0\u1edbc v\u1ec1 k\u1ebft qu\u1ea3 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t l\u00e0 40803. K\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ng\u00e0y ch\u1ee7 nh\u1eadt v\u1ec1 57157. Ta s\u1ebd c\u00f3 \u0111\u01b0\u1ee3c:<\/span><\/p>\n\n- K\u1ebft qu\u1ea3 \u0111\u1ec1 ng\u00e0y th\u1ee9 6 v\u1ec1 03.<\/span><\/li>\n
- Ch\u1ee7 nh\u1eadt \u0111\u1ec1 v\u1ec1 57\u00a0<\/span><\/li>\n<\/ul>\n
\u00c1p d\u1ee5ng c\u00e1ch t\u00ednh ch\u1ea1m \u0111\u1ec1 \u1edf tr\u00ean, ch\u00fang ta s\u1ebd c\u00f3 5+7 = 12, l\u1ea5y 2 gh\u00e9p v\u1edbi s\u1ed1 3 s\u1ebd c\u00f3 \u0111\u01b0\u1ee3c ch\u1ea1m 2 v\u00e0 3 \u0111\u1ec3 \u0111\u00e1nh trong tu\u1ea7n sau.\u00a0<\/span><\/p>\nC\u00e1ch b\u1eaft ch\u1ea1m \u0111\u1ec1 \u0111\u1eb7c bi\u1ec7t s\u1ed1 3<\/em><\/strong><\/span><\/span><\/h3>\nC\u00e1ch b\u1eaft ch\u1ea1m \u0111\u1ec1 chu\u1ea9n n\u00e0y r\u1ea5t hi\u1ec7u qu\u1ea3 v\u00e0 r\u1ea5t d\u1ec5 th\u1ef1c hi\u1ec7n. C\u1ee5 th\u1ec3, anh em h\u00e3y quan t\u00e2m \u0111\u1ebfn t\u1ed5ng c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ng\u00e0y ch\u1ee7 nh\u1eadt v\u00e0 s\u1eed d\u1ee5ng \u0111\u1ec3 \u0111\u00e1nh lu\u00f4n trong tu\u1ea7n h\u00f4m \u0111\u00f3. Theo kinh nghi\u1ec7m c\u1ee7a c\u00e1c chuy\u00ean gia th\u00ec ch\u1ea1m \u0111\u1eb7c bi\u1ec7t n\u00e0y th\u01b0\u1eddng \u0103n trong 3 \u2013 5 tu\u1ea7n. V\u00ec v\u1eady, \u0111\u00e1nh 3 \u2013 5 tu\u1ea7n, sau \u0111\u00f3 ngh\u1ec9 2 \u2013 3 tu\u1ea7n r\u1ed3i m\u1edbi ch\u01a1i l\u1ea1i.<\/span><\/p>\nV\u00ed d\u1ee5:<\/strong>\u00a0Ch\u1ee7 nh\u1eadt gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1 50483. Th\u1ef1c hi\u1ec7n t\u00ednh t\u1ed5ng b\u1eb1ng c\u00e1ch l\u1ea5y 5 + 0 + 4 + 8 + 3 = 20. \u00c1p d\u1ee5ng ph\u01b0\u01a1ng ph\u00e1p b\u1eaft ch\u1ea1m \u0111\u1ec1 \u0111\u1eb7c bi\u1ec7t tr\u00ean, ch\u00fang ta s\u1ebd c\u00f3 \u0111\u01b0\u1ee3c b\u1ed9 s\u1ed1 20, t\u1ee9c l\u00e0 2 ch\u1ea1m l\u00e0 2 v\u00e0 0.<\/span><\/p>\nTh\u00f4ng th\u01b0\u1eddng th\u00ec ng\u00e0y th\u1ee9 2 ho\u1eb7c th\u1ee9 3 k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc s\u1ebd v\u1ec1 \u0111\u1ec1 nh\u01b0 \u00fd.<\/span><\/p>\n